![]() ![]() In order to produce a scatter marker of the same size as a plot marker of size 10 points you would hence call scatter(. So the relationship between the markersize of a line plot and the scatter size argument is the square. In order to obtain a marker which is x points large, you need to square that number and give it to the s argument. S : scalar or array_like, shape (n, ), optional The argument s in plt.scatter denotes the markersize**2. Plt.legend(loc='center left', bbox_to_anchor=(1.1, 0.5), labelspacing=3)īecause other answers here claim that s denotes the area of the marker, I'm adding this answer to clearify that this is not necessarily the case. Thus if we want a circle to appear a factor of n bigger we would increase the area by a factor n not the radius so the apparent size scales linearly with the area.Įdit to visualize the comment by is what it looks like for different functions of the marker size: However it is the second example (where we are scaling area) that doubling area appears to make the circle twice as big to the eye. Similarly the second example each circle has area double the last one which gives an exponential with base 2. The question asked about doubling the width of a circle so in the first picture for each circle (as we move from left to right) it's width is double the previous one so for the area this is an exponential with base 4. Now the apparent size of the markers increases roughly linearly in an intuitive fashion.Īs for the exact meaning of what a 'point' is, it is fairly arbitrary for plotting purposes, you can just scale all of your sizes by a constant until they look reasonable.Įdit: (In response to comment from probably confusing wording on my part. If instead we have # doubling the area of markers Notice how the size increases very quickly. ![]() To see this consider the following two examples and the output they produce. ![]() Because of the scaling of area as the square of width, doubling the width actually appears to increase the size by more than a factor 2 (in fact it increases it by a factor of 4). There is a reason, however, that the size of markers is defined in this way. This means, to double the width (or height) of the marker you need to increase s by a factor of 4. _callback(lambda : self.ax. can be a somewhat confusing way of defining the size but you are basically specifying the area of the marker. Self.cid = ax._connect('draw_event', self._resize) Self.sc = ax.scatter(x,y,s=self.size,**kwargs) import matplotlib.pyplot as pltĭef _init_(self,x,y,ax,size=1,**kwargs): This is a little involved and would work similarly as Plotting a line with width in data units. Hence the following solution would be more generic. In case the axes limits would change or the plot is zoomed, the scatter plot would again have the wrong sizing. The drawback of the above solution is that is fixes the marker size to the size and state of the plot. S = ((ax.get_window_extent().width / (vmax-vmin+1.) * 72./fig.dpi) ** 2)įor some background on how markersize of scatters is used, see e.g. The easy solution here would be to first draw the figure once, then take the axes size and calculate the markersize in points from it. The alternative, if a scatter plot is desired, would be to update the markersize to be in data units. Using scatter with markers of size in data units An easy option is to replace the scatter by a PatchCollection consisting of Circles of radius 0.5. ![]()
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